If [A] doubles in a first-order reaction, what happens to the rate?

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Multiple Choice

If [A] doubles in a first-order reaction, what happens to the rate?

Explanation:
In first-order kinetics, the rate is directly proportional to the concentration of the reactant: rate = k[A]. That means if the concentration of A doubles, the rate doubles as well, since the proportionality constant k stays the same. This linear relationship is what defines first-order behavior. If the reaction were second-order, doubling [A] would quadruple the rate, and if it were zero-order, doubling [A] would leave the rate unchanged.

In first-order kinetics, the rate is directly proportional to the concentration of the reactant: rate = k[A]. That means if the concentration of A doubles, the rate doubles as well, since the proportionality constant k stays the same. This linear relationship is what defines first-order behavior. If the reaction were second-order, doubling [A] would quadruple the rate, and if it were zero-order, doubling [A] would leave the rate unchanged.

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