Which relationship links the rate constant k to the slope m for zero-order or first-order plots?

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Multiple Choice

Which relationship links the rate constant k to the slope m for zero-order or first-order plots?

Explanation:
The key idea is that, for both zero-order and first-order plots, the slope represents the rate at which the concentration changes, and that slope is negative because the concentration decreases over time. In a zero-order plot of [A] versus time, the line has slope -k since d[A]/dt = -k. In a first-order plot of ln[A] versus time, the line has slope -k since d/dt[ln A] = -k. So in either case the slope m equals -k, which means k = -m. The negative sign reflects the decreasing quantity as the reaction proceeds.

The key idea is that, for both zero-order and first-order plots, the slope represents the rate at which the concentration changes, and that slope is negative because the concentration decreases over time. In a zero-order plot of [A] versus time, the line has slope -k since d[A]/dt = -k. In a first-order plot of ln[A] versus time, the line has slope -k since d/dt[ln A] = -k. So in either case the slope m equals -k, which means k = -m. The negative sign reflects the decreasing quantity as the reaction proceeds.

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